This was I think his mistake. I think his formulas were correct. I am not going to try them out tonight as my computer has a problem and I lost my excel progam, and it will let me download things...
Type: Posts; User: mayflow
This was I think his mistake. I think his formulas were correct. I am not going to try them out tonight as my computer has a problem and I lost my excel progam, and it will let me download things...
But science might care that I have a mechanical alarm clock and if I move the hands in their 60:1 ratio, they do cross exactly 11 times in 12 hours. This is a ratio of 1.0909090909... This means to...
Online, most say 22 times per day. This if rounded is a 17% (22/24) differential which fits into my theory of 10/12 or 5/6 which is (if rounded) = 83%. Which is about the ratio of my and my friend's...
First, I think even though we got the exact same answers. I think both my friend and I were off a little, and I think it is related to a clock being divided by 12 major units each being divided by 5...
True, but the question was probably not expressed by me properly. What I meant to ask is when will the hands be next in the same position on the clock? I guess when will the minute hand cross over...
y=60 represents the minute hand of the clock. It is ten minutes past 8. This represents ten of 60 minutes in the hour which is 1/6 of an hour. 1/6 of 360 degrees of a circle is 60, just as 2/3 of a...
Oh crap. I think I know how he got 240. the little hand is the start at 8:40. 40 minutes is 2/3 of an hour. 2/3 of 360 (degrees in a circle) is 240.
So someone said to me "If a clock has its little hand just past 8 and the big hand at 8:10, how long before the two hands are in the same position?" I thought it would be a little more than 30.5...