THANK YOU SO MUCH! It all makes sense now! Really really appreciate your help! Thanks a bunch!
Type: Posts; User: BitRunner
THANK YOU SO MUCH! It all makes sense now! Really really appreciate your help! Thanks a bunch!
According to my teacher, that is the correct answer :O! (Even my teacher couldn't get it!)
One question though, I followed up until near the end of the calculation using the quadratic formula. How...
I doubt this has any relevance to the question. It's an advanced functions (12) question; not this advanced though lol
I'm still not too sure. If it is possible, could you show me how you would take this step by step? I understand that BOQ is the right triangle; are the rations still the same (of sin and cos)? In any...
The green arrow has no more significance other than what I pointed out. The original diagram did not have the green arrow in the diagram. I drew the arrow because the diagram was too small.
And that should give me r? :)
One question. Triangle QPB is not a right triangle. Why is it that sin of QPB and cos of QPB give those values?
(r/26)^2 + (18/2r)^2 = 1?
Okay, so how would I set up the values in the identity? No matter what I did, I couldn't see what to do.
A bit. Could you give me a few more hints please :) and is QPB angle P in triangle QPB?
I still can't get it :( I tried
Wow, how smart lol! I've done that, what next?
Yes, I see it now :D
Ahh! Yes I see that now! What happens next?
It's just showing that the line going down the middle of the circle is the radius
Oops! Sorry! The question is to find the distance between P and Q.
I have been attempting this question for several days now! I haven't a single clue as to how to get the final answer. It's beginning to get frustrating, haha, and I really want to understand how this...