03-01-2014, 09:29 AM
Originally Posted by

**Sundermeyer**
I have a basic understanding of quantum computing

Hmmm. Your question suggests to me that you don't. What you describe is simply two bits, and a qubit is not equivalent to two bits. A qubit is a single bit such that the 0 and 1 states are in quantum superposition, which makes a qubit a non-classical object. Associated with the quantum superposition is a complex-valued probability amplitude that determines the contribution of the 0 and 1 eigenstates to the quantum superposition. Depending on the accuracy required, the specification of the probability amplitude would require several bits for the information content of the qubit to be classically contained.

If one considers multiple qubits, then quantum entanglement of the qubits means that each possible combination of classical bit-values are in quantum superposition, with each combination having its own complex-valued probability amplitude. This means that the number of classical bits required to specify the information content of a given number of qubits increases *exponentially* with the number of qubits.

A tensor equation that is valid in *any* coordinate system is valid in *every* coordinate system.