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Thread: Problem with oblique projection derivation

  1. #1 Problem with oblique projection derivation 
    Junior Member
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    Apr 2014
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    Hi,
    Can some body plz guide me how the values of xp and yp in case of oblique parallel projection is equal to:

    xp= x + L cos (phi)
    yp= y + L sin (phi)



    This is mentioned in slide 50 of following link:
    http://ae.sharif.edu/~aerocad/3D%20Viewing.pdf

    I have studied that oblique projection is the sum of orthogonal and shear. Orthogonal is same as "x" but i cant understand how we got "L cos(phi)".

    I would be glad to hear from some body in this regard.

    Zulfi.
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  2. #2  
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    Drop a line down from (xp, yp) onto the xv axis and call the point (xv, yv)., where xv=px. Then consider the triangle made by the points
    (x,y) (xp, yp) and (xv, yv).
    Cos phi = (xv -x)/L
    Xv=xp =x + Lcos phi
    zak100 likes this.
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  3. #3  
    Junior Member
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    Apr 2014
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    Hi
    Thanks. Great work. I tried but i didnot find this calculation any where. Just one thing plz correct me:
    where xv=px
    Should i use Xp instead of px.

    Thanks again for this calculation.

    Zulfi.
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  4. #4  
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    Yes!
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  5. #5  
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    Thanks for your help. I think i am bale to understand all components of this figure. This problem is solved now.

    Zulfi.
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