1. non-dimensionalisation equation:
\frac {du}{d\tau}=\frac{\overline{\lambda}_{1} u}{u+1} -\overline{r}_{ab}uv -\overline{d}u

where $\overline{\lambda}_{1}= \frac {\lambda_{1}}{\lambda_{2} K_{1}}$
Another non-dimensionalisation equations
\frac {dv}{d\tau}=(1-v) -\overline{r}_{ba}uv

THE REAL QUESTION IS: calculate the steady state $(u_4,v_4)$ and $(u_5,v_5)$? Discuss the occurrence of these steady-states in respect of any relationships between the non-dimensional. Note you are not required to determine the stability of these two states.

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I have already calculated the steady-states of $(u_4,v_4)$ and $(u_5,v_5)$ which are

$(u_4,v_4)$ =($\frac{\overline{\lambda}_{1} - \overline{d} -\overline{r}_{ab}}{\overline{r}_{ab} + \overline{d}} ,1)$

$(u_5,v_5)$ =($\frac{\overline{\lambda}_{1} - \overline{d} -\overline{r}_{ab}}{\overline{r}_{ab} + \overline{d}}$ ,$1 - \overline{r}_{ba} \frac{\overline{\lambda}_{1} - \overline{d} -\overline{r}_{ab}}{\overline{r}_{ab} + \overline{d}}$ )

I HAVE ALREADY CALCULATED $(u_1,v_1)$ and $(u_2,v_2)$ and $(u_3,v_3)$ but i an not interested to talk about their steady-state with respect to non-dimensional parameters.

here are the non-dimensional parameters which I have also determined:

$\overline{\lambda}_{1}= \frac {\lambda_{1}}{\lambda_{2} K_{1}}$

$\overline{d}= \frac{d}{\lambda_{2}}$

$\overline{r}_{ab} = \frac{\overline{r}_{ab} K_{2}} {\lambda_{2}}$

$\overline{r}_{ba} = \frac{\overline{r}_{ab} K_{1}} {\lambda_{2}}$

can anyone please please help me in discussion of these steady states $(u_4,v_4)$ and $(u_5,v_5)$ with the above non-dimensional parameters .

2. why is it coming on latex form?

3. Originally Posted by grandy
why is it coming on latex form?
Write it in La Tex from the beginning.

4. Originally Posted by Robittybob1
Write it in La Tex from the beginning.
its written la tex and paste it here

5. Originally Posted by grandy
its written la tex and paste it here
Do a little la Tex on the site and see what formatting parts you have missed.

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