# Thread: Find the equivalent resistance.

1. The current flows from Point A to B.
Here is the image: Download IMG 20140814 075906.jpg

2. Not really knowing what the problem is, Lets give this a try together.

My first step is to make a diagram (or part of it) readable.
Something like this....

Doesn't that look a lot better and easier to solve.

First we need to replace R1 & R2 since they are parallel

1/r12 = 1/r1 + 1/r2
in your case
1/r12 = 1/2 + 1/2 = 2/2 = 1

r12 = 1/1 = 1 ohm

That should be clear as the current has 2 paths to take and therefore 2 resistors in parallel only has the resistance of half of one... at least in this case since they are the same

Now things really start to look easy, don't they...

r123 = r12 + r3 since they form a series

r123 = 1 + 2 = 3 ohm

Since i have done most of the hard work, you can calculate r1234 by yourself. If you need advanced help, just ask... I am a technician; I can make you harder exercises, if you still don't understand.

This is a very important base part for understanding electricity flow make sure you understand

when 2 or more resistors are in parallel

1/Replacement = 1/R1 + 1/R2 + 1/R...

when they are in series

Replacement = R1 + R2 + R...

And make an easy to read diagram....

Kind regards

Napivo

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