i m not able to solve this problem so can someone help me please

the question is as follows:-

Under the action of a force,a 2 kg body moves such that its position x as a function of time t is given by x=t^3/3,where x is in meters and t in seconds.Work done i first 2 sec is??

a)1600J

b)160J

c)16J

d)1.6J

please help me with it

Thnx in advane

i m not able to solve it