1. Example:

The kinetic energy in a satellite is the same the machine gun attached to the satellite. Then the machine gun shoots a bullet caliber 60 and produced a thrust of more or less 20 kg.

My question is: this shot will propel the satellite at rest, or in motion?

2. The statement is confusing. Firing a bullet will add momentum to the machinegun + satellite in the opposite direction from the bullet.

3. Originally Posted by mathman
The statement is confusing. Firing a bullet will add momentum to the machinegun + satellite in the opposite direction from the bullet.
Okey. Then is a machine gun a space propellant?

4. Yes. Newton: opposite and equal reaction and all that.

5. Using a machine gun as space propellant, can you make me a calculation?

How long can get to Mars, using the following:

1.- 540,000 bullets caliber 60,
2.- a machine gun,
3.- a robot finger,
4.- and shoot (a bullet each one (1) minute)

Very affectionately,
Víctor Elias Espinoza Guedez
08 October 2014

6. I won't be doing the math, but I can see you already need more data:

a. How much mass is there in the rest of the vehicle? (Will affect velocity given by each bullet).
b. How much mass is there in one bullet?
c. What's the muzzle velocity of the gun?
d. What's your intended trajectory? (Different paths have different costs).
e. What's your start point? (e.g. maybe you won't even be able to get out of Earth orbit).

etc.

(Also, with the given limitation on the number of bullets, maybe there's just not enough.)

7. Using a machine gun as space propellant, can you make me a calculation?

How long can get to Mars, using the following:

Weight = A Space Shuttle + 540,000 bullets
Distance = 78.300.000 km
Force = 200 Newton. Shoot a bullet each one (1) minute. Caliber 60 more or less.
Time = ?

Starting point: orbit of the planet Earth
Arrival point: orbit of the planet Mars

Thank you...

Very affectionately,
Víctor Elias Espinoza Guedez
TSU in computer science

8. Originally Posted by victorespinoza72
Using a machine gun as space propellant, can you make me a calculation?

How long can get to Mars, using the following:

1.- 540,000 bullets caliber 60,
2.- a machine gun,
3.- a robot finger,
4.- and shoot (a bullet each one (1) minute)

Very affectionately,
Víctor Elias Espinoza Guedez
08 October 2014
It may already be on Mars.

9. Using a machine gun as space propellant, can you make me a calculation?

How long can get to Mars, using the following:

Weight = A Space Shuttle + 540,000 bullets
Distance = 78.300.000 km
Force = 200 Newton. Shoot a bullet each one (1) minute. Caliber 60 more or less.
Time = ?

Starting point: orbit of the planet Earth
Arrival point: orbit of the planet Mars

Thank you...

Very affectionately,
Víctor Elias Espinoza Guedez
TSU in computer science

10. Look up the muzzle energy of a 0.600 rifle bullet. See if 540 000 of that can accelerate a 10 pound rifle to escape velocity. Start with that.

11. Yes there is acceleration, because there is nothing in the space, which slow down the momentum of 200 Newton.

12. Where did you get the 200 Newtons from?

13. Originally Posted by pzkpfw
Where did you get the 200 Newtons from?
Of 20 kilograms of force to the side opposite the bullet caliber 60. This multiplied by the gravity of 9.8 m/s.

F = g . m

14. Muzzle energy - Wikipedia, the free encyclopedia

From rifle ballistic table a 0.600 caliber rifle is 1950 fps / 7596 ft lbs at muzzle

How much energy to you need get your mass up to 7 miles per second or 25 000 miles per hour?

Low earth orbit is 17 000 miles per hour 5 miles per second

Is the rifle 10 pound or is it that 20 kg (44 pounds) you came out with?

Do you know SI to Imperial conversions of units?
You don't do what you are asked to do? How old are you?

15. Originally Posted by pikpobedy
Muzzle energy - Wikipedia, the free encyclopedia

From rifle ballistic table a 0.600 caliber rifle is 1950 fps / 7596 ft lbs at muzzle

How much energy to you need get your mass up to 7 miles per second or 25 000 miles per hour?

Low earth orbit is 17 000 miles per hour 5 miles per second

Is the rifle 10 pound or is it that 20 kg (44 pounds) you came out with?

Do you know SI to Imperial conversions of units?
You don't do what you are asked to do? How old are you?
I do not understand you...

I speak of the strength that I get to the opposite side of the bullet, which is more or less 20 kg. Calculating mentally.

16. There is no point in continuing if you cannot read and understand what I wrote. Sorry.
I asked you to do things and you persist in ignoring the instructions.

17. Originally Posted by pikpobedy
There is no point in continuing if you cannot read and understand what I wrote. Sorry.
I asked you to do things and you persist in ignoring the instructions.
I'm sorry, but I do not understand what you ask me.

Very affectionately,
Victor Elias Espinoza Guedez
Friend, I did not understand the translator. You understand.

18. After firing in the universe is there acceleration? Because pushing the ship with a force of 20 kg, it should keep that speed, up to the next minute for the next shot.

19. I think you would have to calculate the ratio of difference in mass of the bullets to the entire mass of the ship including the guns and the cargo. Also, space is not really a vacuum and there are particles and probably molecules in space, so it is not totally frictionless, and this will be complicated further when encountering the atmospheres and gravity forces of planets, asteroids and what have you all.

20. Outer space as in interplanetary space is better vacuum than anything artificially made.

The mass of the ammunition in this case is important. A rifle round (aka cartridge) is comprised of a brass casing (holding everything together) , primer (encasing the primary explosive), propellant (charge of cordite) and a projectile (bullet made of brass and lead ). You can surmise that most of the mass is not fuel, thus it's specific energy content is not very good as a space vehicle propellant. You know that after firing a weapon of the type the bullet shoots out the barrel and the empty shell casing is ejected out of the side. Both have a reaction force. Keeping the shell casing in the vehicle would reduce that reaction but the mass kept would be part of the total mass for the entire voyage. If ejected they would impart impulses opposite to the ejection that could be used for additional thrust or at least corrected for so as not to affect trajectory.

As for the OP. Forget it. There is nothing coherent there and after. The guy does not do step one, he adds conflicting constraints in subsequent posts and just carps about being helpless. Maybe he is a bot being tested here.

21. And if we put 5 machine guns, increase the thrust force to 1000 Newton. Can this help to push a ship in space.? And get more acceleration.

*******************************************

Using a machine gun as space propellant, can you make me a calculation?

How long can get to Mars, using the following:

Weight = A Space Shuttle + 540,000 bullets
Distance = 78.300.000 km
Force = 1000 Newton. Shoot a bullet each one (1) minute. Caliber 60 more or less.
Time = ?

Starting point: orbit of the planet Earth
Arrival point: orbit of the planet Mars

Thank you...

Very affectionately,
Víctor Elias Espinoza Guedez

USING THE FOLLOWING RIFLE:

http://img.webme.com/pic/t/teoria-es...rifle-bala.jpg

USING THIS IDEA:

The put images does not work.

22. Dear Sirs students and graduates in physics,

A question: What distance travel a bullet, in the outer or empty space? and, At what speed?

23. In the absence of mass to bang into or gravity to alter it's velocity, it'll go "forever" at the muzzle velocity of the weapon. (Which I'd expect to be a bit higher in space than when fired in an atmosphere).

Of course, those conditions (truly empty space, "forever") are unlikely to occur. I'd expect a bullet fired from anywhere within the solar system, for example, would not escape the solar systems gravity.

Escape velocity - Wikipedia, the free encyclopedia

Solar system escape velocity: 492–594 km/s

Barrett M82 - Wikipedia, the free encyclopedia

Muzzle velocity of Barrett light 50: 853 m/s

24. What would happen with the following idea: shall we go to the speed of light?

PROPELLANT AT THE SPEED OF LIGHT

WHAT DISTANCE HAS THIS BULLET?

http://img.webme.com/pic/t/teoria-es...ansparente.jpg

I hearing opinion to perform other detonations.

My idea is to place 10 giant guns on the sides of the space shuttle.

This idea is possible.

I'm not physical, but I think this bullet blue with the space shuttle, will come to the planet Mars. I repeat I am not physical, but doing this shot in the orbit of the Earth, out of gravity, this bullet does nothing to stop it, because the vacuum not braked to a bullet.

There are details that refine to make this idea work, one of them is to climb a Cannon equal to of a military weapon. Then you need to join the bullet with functions to stop and maneuver during his trip at a great speed.

The other is how will return the blue bullet with the space shuttle, because you'll need another Cannon for the return.

To get to the planet Mars, you need a lever and this is the lever.

Patent pending.
Invented by Victor Elias Espinoza Guedez

Very affectionately,
Víctor Elias Espinoza Guedez
09 October 2014

25. Originally Posted by pikpobedy
Outer space as in interplanetary space is better vacuum than anything artificially made.

The mass of the ammunition in this case is important. A rifle round (aka cartridge) is comprised of a brass casing (holding everything together) , primer (encasing the primary explosive), propellant (charge of cordite) and a projectile (bullet made of brass and lead ). You can surmise that most of the mass is not fuel, thus it's specific energy content is not very good as a space vehicle propellant. You know that after firing a weapon of the type the bullet shoots out the barrel and the empty shell casing is ejected out of the side. Both have a reaction force. Keeping the shell casing in the vehicle would reduce that reaction but the mass kept would be part of the total mass for the entire voyage. If ejected they would impart impulses opposite to the ejection that could be used for additional thrust or at least corrected for so as not to affect trajectory.

As for the OP. Forget it. There is nothing coherent there and after. The guy does not do step one, he adds conflicting constraints in subsequent posts and just carps about being helpless. Maybe he is a bot being tested here.
Thanks for the vacuum article. The mass of the impelled bullet would have no weight in a free space vacuum, right? Without gravity, no weight. What force is supposed to have an opposite reaction then?

In a gravitational field, the casing of the bullet may have even more mass than the bullet itself and either would be insignificant to the weight of the barrel of the gun, much less all the other unfired bullets on board, and the other cargo or the ship iteslf.

I have an off qestion remark about the calibre of a gun. In the article you posted on this, in the image, the 22 bullet looked to be so much smaller in case diameter than a 223 did, so the calibre as I thought was a dimension of the bore and casing is really the measurement of the base of the projectile (slug), right?

26. victorespinoza72 : "What would happen with the following idea: shall we go to the speed of light?"

Why would you get that fast?

How is that going to be any better than the rockets we've already got?

How could putting all the energy into one "bang" not destroy the vehicle?

27. Mass is quantity of matter. It is independent of gravitational field. Force is mass x acceleration. Weight on earth is mass x gravitational acceleration.

Interestingly: traditional units and popular usage change with time. Who uses slugs? Who uses newtons in real life (except in torque newton-meters.

Anyway a lot unit conversion data contain pound mass (lbm) , pound force lbf) , kilogram mass (kgm), kilogram force (kgf) and of course newtons grams, etc.

How much does a big guy weigh: 980 newtons = 100 kilogram force (aka kilopond) = 220 pounds force (aka pound)

Slug (mass) - Wikipedia, the free encyclopedia

28. I have an off qestion remark about the calibre of a gun. In the article you posted on this, in the image, the 22 bullet looked to be so much smaller in case diameter than a 223 did, so the calibre as I thought was a dimension of the bore and casing is really the measurement of the base of the projectile (slug), right?

Bore or projectile diameter are somewhat interchangeable terms referred to as caliber in rifles. Rifle barrels are rifled, meaning they have a helix groove pattern inside that makes the bullet revolve to give it gyroscopic stability. So a rifle barrel has two diameters one at top and the other at bottom of grooves.

A 22 bullet is for all intents and purposes 0.22 inches in diameter. A 0.223 Remington is very similar to a 5.56 NATO round. Both 0.22 inches or 5.56 mm in diameter.

Caliber for Naval canons is the ratio length to diameter. Iowa class battle ships had 16 inch guns that were 50 cailber. This 16/50.
Caliber (artillery) - Wikipedia, the free encyclopedia

For shot guns you have the 410 which is 0.41 inch in diamer but the 28, 20, 16, 12 and 10 gauge. In this case the gauge means how many lead balls of the diameter of the bore would weigh one pound. The popular 12 gauge the amount of balls would be 12. The smaller 20 gauge the amount of balls would be 20. This is an old system reverting back more than one hundred years.

Gauge (bore diameter) - Wikipedia, the free encyclopedia

29. Oh duh. I see. The barrel is the diameter of the base of the projectile and the rifling spins it (rifle or handgun) to keep the trajectory more true - the shotgun maybe has not rifling (little twists in the barrel?

The casing simply then is ejected as a waste product after holding in the powder to act as an enclosement for the powder to react against to propel the bullet?

30. The rifle barrel is grooved. The bullet (projectile) is deformed from a circular cross section into one that is the "mate" of the grooved interior of the barrel. Thus a bit of squeezing and plastic deformation of the bullet. The bullet's circular diameter would be engineered to as to have an effective fit into a grooved barrel.

The twist rate is very obtuse. 1 revolution in 8 inches or so.
Rifling - Wikipedia, the free encyclopedia

The casings are scrapped or can be recovered, reloaded and reused.

31. What is meant by plastic deformation?

32. Plastic deformation is permanent deformation. Solids can flow under pressure. For example toothpaste, peanut butter, putty, clay, lead, aluminium, copper, steels, polyamide etc can be made deformed permanently without breaking. They can flow into molds while still solid.
pottery making
Extrusion process, rolling mill

33. What would happen with the following idea: shall we go to the speed of light?

PROPELLANT AT THE SPEED OF LIGHT

WHAT DISTANCE HAS THIS BULLET?

http://img.webme.com/pic/t/teoria-es...ansparente.jpg

I hearing opinion to perform other detonations.

My idea is to place 10 giant guns on the sides of the space shuttle.

This idea is possible.

I'm not physical, but I think this bullet blue with the space shuttle, will come to the planet Mars. I repeat I am not physical, but doing this shot in the orbit of the Earth, out of gravity, this bullet does nothing to stop it, because the vacuum not braked to a bullet.

There are details that refine to make this idea work, one of them is to climb a Cannon equal to of a military weapon. Then you need to join the bullet with functions to stop and maneuver during his trip at a great speed.

The other is how will return the blue bullet with the space shuttle, because you'll need another Cannon for the return.

To get to the planet Mars, you need a lever and this is the lever.

Patent pending.
Invented by Victor Elias Espinoza Guedez

Very affectionately,
Víctor Elias Espinoza Guedez
09 October 2014

34. A question: Time to get to Mars?

a. Escape velocity, which is 11.2 km/s on Earth

b. The acceleration (a) would theoretically be more than 1000 m/s2

c. Distance: 78.300.000 Km

d. Starting point: orbit of the planet Earth

e. Arrival point: orbit of the planet Mars

f. Time = ?

..."i.e. squashed like a cockroach underfoot"

The pressure inside the spaceship is that crushes it.
The Astronaut carries the same speed of the spacecraft.
With a front pressure protector. The pressure to crush the astronaut must be avoided.

The astronaut who crushes? The air inside the space shuttle? What you need to do, is to protect the astronaut, of the air inside the spaceship. Because the air is not moving.

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